Nº 21 Bizya Buyannemeth ,Peter Krug and Mario García

Draw

Section B.2.

Bizya Buyannemekh (Mongolia) Peter Krug (Austria) and Mario García (Argentina)

wKd6,Bh3,Rf1,Pc7,f7/bKg7,Qb3,Nd2,d7,Pf2

Twin A

1.c8Q!
1.f8Q+? Nxf8 2.c8Q Qd3+ 3.Kc6 Nxf1 4.Bxf1 Qxf1–+

1…Nc4+
1…Qg3+ 2.Kc6 Ne5+ 3.Kb7 Qf3+ 4.Ka6=

2.Kxd7 Nb6+ 3.Kc7!!
3.Kd8? Nxc8 4.f8Q+ Kxf8 5.Rxf2+ Kg7 6.Rg2+ Kh6 7.Bxc8 Qd5–+

3…Nxc8 4.f8Q+ Kxf8 5.Rxf2+ Ke7 6.Re2+ Kf6 7.Rf2+ Ke5
main 7…Kg5 8.Rg2+ Kh4 9.Bxc8 Qc4+ 10.Kb8!=

8.Bxc8 Qc3+ 9.Kb8! Qb4+ 10.Ka8! Qa5+ 11.Kb7 Qb5+ 12.Ka8 Kd6 13.Rf7 Qe8 14.Rd7+ Kc6 15.Kb8= positional draw

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Twin B
With bishop in e8

wKd6,Be8,Rf1,Pc7,f7/bKg7,Qb3,Nd2,d7,Pf2

1.c8Q!
1.Rxf2? Ne4+! (1…Nc4+? 2.Kxd7 Qd3+ 3.Kc6 Qd6+ 4.Kb5 Qb6+ 5.Kxc4 Qxf2 6.Kb5=) 2.Ke7 Qb4+ 3.Kxd7 Qd4+–+

1…Nc4+ 2.Kxd7 Nb6+
2…Qb5+ 3.Kd8=

3.Kd8 Qd5+
3…Qd3+ 4.Bd7=

4.Bd7 Nxc8
4…Qg5+ 5.Ke8 Qe5+ 6.Be6 Qb5+ 7.Bd7 Qe2+ 8.Be6=

5.f8Q+ Kxf8 6.Rxf2+ Kg7 7.Rf5 Qg8+ 8.Be8 Qe6
8…Qh8 9.Rf7+ Kh6 10.Rf5 similar to solution

9.Bd7 Qg8+ 10.Be8 Qh8 11.Rf7+ Kh6 12.Rf5!
12.Rc7? Nd6!–+

12…Qc3 13.Rh5+ Kg7 14.Rg5+ Kf6 15.Rg6+ Ke5 16.Rc6= positional draw