Nº18 Michal Hlinka & Luboš Kekely

Draw

Section B.2.

Michal Hlinka & Luboš Kekely (Slovakia)

wKc1,Bf4,Rb1,Pb2,g3/bKg2,Nf2,Bh6,Pa6,b3,h3

1.Kd2! refutation to capture
1.Bxh6? Ne4 2.Kd1 Kf3 3.Rc1 h2–+

1…Bf8
1…Bg7 2.g4=

2.g4!
2.Kc3? Ng4–+
2.Be3? h2 3.g4 Bb4+ 4.Ke2 Nxg4 5.Bf4 h1Q–+

2…Kf3 3.Be5 Bb4+ 4.Bc3
4.Kc1? Nd3–+

4…Bc5 5.Be5!
5.Rf1? Be3+ 6.Ke1 h2 7.g5 Ke4 8.Ke2 h1Q 9.Rxh1 Nxh1 10.g6 Ng3+ 11.Ke1 Nf5 12.g7 Ne7–+

5…Bb4+ 6.Bc3 Ne4+
6…Bd6 7.Bd4!=

7.Kd3 Bxc3 8.bxc3 a5
8…h2 9.c4 a5 10.g5! Nxg5 11.c5 Nh3 12.c6 Ng1 13.Rxb3 h1Q 14.c7 Qh8 15.Kc4+! Ke4 16.Rb8 Qd4+ 17.Kb5=

9.g5!
9.c4? a4 10.g5 a3 11.g6 b2 12.g7 a2 13.Rxb2 a1Q 14.g8Q Qd1+ 15.Rd2 Qxd2#

9…Nxg5 10.c4 a4
10…h2 11.c5 as after 8…h2

11.c5 a3 12.c6
12.Kc4? b2 13.Kb3 Ne4 14.Kxa3 Nd2 15.Kxb2 Nxb1 16.c6 Nd2 17.c7 Nc4–+

12…a2
12…Ne6 13.Kc3=

13.Rf1+! Kg2 14.Ra1!
14.c7? b2 15.c8Q b1Q–+

14…h2
14…Ne6 15.Kc3=

15.c7 h1Q 16.Rxh1 Kxh1 17.c8Q excelsior, for example 17… a1Q 18.Qc6+ =